x^2=18x-8

Solution for x^2=18x-8 equation:

x^2=18x-8

We move all terms to the left:

x^2-(18x-8)=0

We get rid of parentheses

x^2-18x+8=0

a = 1; b = -18; c = +8;
Δ = b2-4ac
Δ = -182-4·1·8
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{73}}{2*1}=\frac{18-2\sqrt{73}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{73}}{2*1}=\frac{18+2\sqrt{73}}{2}
$